Its Fun to Program with C#
Monday, 14 December 2015
How to arrange numbers numerically
Hello guys you can arrange numbers numerically from an array using bubble sort method.
Its Simple and easy. Just Watch the video and view the codes below
namespace Bubble_Sort
{
class Program
{
static void Main(string[] args)
{
int[] save = { 2, 1, 6, 7, 8, 9 };
int hold;
for (int i = 0; i < save.Length; i++)
{
for (int j = 0; j < save.Length; j++)
{
if (save[i]<save[j])
{
hold = save[i];
save[i] = save[j];
save[j] = hold;
}
}
}
foreach (var item in save)
{
Console.Write(item+"\t");
//Displays the arranged numbers
}
Console.ReadLine();
}
}
}
Thanks for watching, visit csharpprogrammingisfun.blogspot.com
Monday, 10 August 2015
How to create a Bisection Method Scheme of any power in C#
BISECTION METHOD USING C#
Here's the Code
using System;
namespace
BisectionMethod
{
class Program
{
static void Main(string[] args)
{
string retry = "";
do{ try
{ float y1 = 0, y2 = 0;
//collect inputs
Console.Write("\n1st
Interval: ");
float x1 =
float.Parse(Console.ReadLine());
Console.Write("2nd
Interval: ");
float x2 =
float.Parse(Console.ReadLine());
float x0 = 0, y0 = 0;
Console.Write("Highest
power in equation: ");
int pwr =
int.Parse(Console.ReadLine());
//store in an array
int[] coe = new int[pwr + 1];
//calculate values of y1
and y2 using for loop
for (int i = 0; i < coe.Length; i++)
{ if (i == 0) { Console.Write("Value of
constant: "); }
else{Console.Write("Coefficient of
variable with power {0}: ", i);}
coe[i] =
int.Parse(Console.ReadLine());
y1 += (float)(coe[i] *
Math.Pow(x1, i));
y2 += (float)(coe[i] *
Math.Pow(x2, i));
} //determine negative
if ((y1 * y2) < 0)
{Console.WriteLine("There is a root between intervals");
while (true)
{//midpoint (x0)
x0 = (x1 + x2) / 2;
for (int i = 0; i
< coe.Length; i++)
{ y0 +=
(float)(coe[i] * Math.Pow(x0, i)); }
if (y0 * y1 <
0)//check for -ve product
{ x2 = x0; }
else{ x1 = x0;}
//approximate y to
6 decimal places
y0 =
(float)Math.Round(y0, 6);
//if y0=0 therefore
root is x0
if
(y0 == 0) { Console.WriteLine("\n The Root is {0}", x0); break; }
y0 = 0;
//reset y0 back to zero in
order to avoid accumulation of result
} }
else{ Console.WriteLine("There
is NO root between intervals"); }
}
catch {
Console.WriteLine("\a\a\a Error \nInvalid Input"); }
Console.Write("\nDo
you wish to try again, type \"Yes\" or otherwise to quit: ");
retry = Console.ReadLine().ToUpper();
} while (retry == "YES");
}
}
}
VIDEO ON YOUTUBE
Happy Programming!!!
Create a Regular Falsi Method Scheme in C#
REGULAR
FALSI METHOD
using System;
namespace
RegularFalsiMethod
{
class Program
{
static void Main(string[] args)
{
string retry = "";
do {
try
{ float y1 = 0, y2 = 0;
//collect inputs
Console.Write("\n1st
Interval: ");
float x1 =
float.Parse(Console.ReadLine());
Console.Write("2nd
Interval: ");
float x2 =
float.Parse(Console.ReadLine());
float x0 = 0, y0 = 0;
Console.Write("Highest
power in equation: ");
int pwr =
int.Parse(Console.ReadLine());
//store in an array
int[] coe = new int[pwr +
1];
//calculate values of y1
and y2 using for loop
for (int i = 0; i <
coe.Length; i++)
{ Console.Write("Value
with power {0}: ", i);
coe[i] =
int.Parse(Console.ReadLine());
y1 += (float)(coe[i] *
Math.Pow(x1, i));
y2 += (float)(coe[i] *
Math.Pow(x2, i));
}
//determine negative
if ((y1 * y2) < 0)
{ Console.WriteLine("There is a root btw
intervals");
while (true)
{//midpoint of line
x0 = ((x1 * y2) -
(x2 * y1)) / (y2 - y1);
for (int i = 0; i
< coe.Length; i++)
{ y0 +=
(float)(coe[i] * Math.Pow(x0, i)); }
if (y0 * y1 < 0)//check
for -ve product
{ x2 = x0; }
else {x1 = x0; }
//approximate y to
6 decimal places
y0 = (float)Math.Round(y0,
6);
//if y0=0 therefore
root is x0
if (y0 == 0) { Console.WriteLine("Root is
{0}", x0); break; }
y0
= 0;//reset y0 back to zero in order to avoid accumulation of result
}
}
else {
Console.WriteLine("There is NO root btw intervals"); }
}
catch {
Console.WriteLine("\a\a\a Error \nInvalid Input"); }
Console.Write("\nDo you wish to try again, type \"Yes\" or
otherwise to quit: ");
retry =
Console.ReadLine().ToUpper();
} while (retry == "YES");
}
}
}
Happy CODING!!!
Thursday, 6 August 2015
CREATE A SIMPLE SIMULTANEOUS EQUATION CALCULATOR WITH C#
Hello guys first what is a simultaneous equation: This
involves the calculation of more than one equation with unknowns
simultaneously.
Back to c-sharp programming, first you need to solve the equation in terms of its constants as shown below
Just like a pseudocode…..
Here is the code
using System;
namespace Simultaneous_Equation
{
class Program
{
static void
Main(string[] args)
{
Console.WriteLine("Welcome to Simultaneous Equation Solver");
//prints the message in the quote
string choice;
do
{
/*(multi line comment) a do loop= runs the code in the block and
then checks if the condition in the while loop is met to run again else it
breaks out of the loop*/
try
{
//try and catch looks for exception and the catches it, the
prints the //message in the catch block.
Console.WriteLine("Input in the format Ax + By = C");
Console.Write("x1= ");
int A
= int.Parse(Console.ReadLine());
Console.Write("y1= ");
int B
= int.Parse(Console.ReadLine());
Console.Write("c1= ");
int C
= int.Parse(Console.ReadLine());
Console.Write("x2= ");
int D
= int.Parse(Console.ReadLine());
Console.Write("y2= ");
int E
= int.Parse(Console.ReadLine());
Console.Write("c2= ");
int F
= int.Parse(Console.ReadLine());
float
x, y;
// equate the variable in terms of the constant
y =
((A * F) - (C * D)) / ((A * E) - (B * D));
if (A
== 0) { x = (F - (E * y)) / D; }
else {
x = (C - (B * y)) / A; }
Console.WriteLine("The value of x = {0}\nThe value of y =
{1}", x, y);
}
catch {
Console.WriteLine("Input is either wrong or not a simultaneous equation");
}
Console.WriteLine(" TRY AGAIN?? Type yes else quit");
choice =
Console.ReadLine().ToLower();
} while
(choice == "yes");
Console.ReadKey(true);
}
}
}
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